PETIN M.I.

PETIN - METON calendar

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The definition of a lunar and solar dates.

Initial data:   Date 15, Month 6, 2005 AD (lunar calendar).

Date 01, Month 1,       1 AD (lunar calendar)  -  1 721 436 JD

January 01,                   1 AD (solar calendar)  -  1 721 426 JD

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What is a solar date X, which according to

a date 15,  Month 6, 2005 AD ?

I.  The subtraction of dates:.

1.   Date 15, Month 6,   2005 AD   .. (the sum)

-  Date 01, Month 1,         1 AD  ... (the augend)

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There are 14 days and 5 lunar months and 2004 years between date 01, Month 1, 1 AD

and date 15 Month 6, 2005 AD  (SimpleM),   i.e.:

14 days , 5 months , 2004 lunar years ……….(the addend)

II.  The definition of  JD value  for the above addend.

2.   2004  : R1 = 6,59,  where:  R1 = 304 from

for interval of (304 – < 6 384 ) years.

We take 6 instead of  6,59 and

6 x 304 = 1824 years

6 x R2  = 666 210 days,  where:  R2  = 111 035 from the table 6

for interval  of  (304 – < 6 384 ) years.

3.   2004 – 1824 = 180 years

4.   180 : R= 3,16,  where:  R1 = 57 from the table 6

for interval  of  (>57) –  285 years.

We take 3 instead of  3,16 and

3 x R1 = 171 years

3 x R2  = 62 457 days,  where:  R2  = 20 819 from the table 6

for interval  of  (>57) – 285 years.

5.        180 – 171 = 9 years  corresponds to 3249 days (table 5 - http://Petin21Mikhail.narod.ru/index.htm  )

6.    The sum of days

666 210

62 457

3 249

148     correspond to  fife  months (see point 1 and

14       (see point 1 )

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732 078 days, i.e. the  JD  value  between date 01, Month 1, 1 AD (or January 11, 1 AD,

JD = 1 721 436 ) and  date 15, Month 6,  2005 AD.

III.  The definition of  JD for date 15, Month 6,  2005.

7.   732 078        i.e. addend,          JD

1 721 436,       i.e. augend           JD for date 01, Month 1, 1 AD (or January 11, 1 AD)

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2 453 514  days,,  i.e. the sum  -  JD for date 15, Month 6,  2005.

IV.  The passing  from date 15, Month 6,  2005 AD (JD = 2 453 514 )  to  the Gregorian date X

8.     2 453 514  days ,  i. e.  JD  for date 15,  Month 6,  2005 AD  (the sum)

- 1 721 426,  i.e.  JD  of   January  01, 1 AD                       ( the augend)

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732 088  days              …………………………............(the addend)

9.   732 088 : K2 =5, 011,     where:  K2 = 146 097 from

for interval  of 146 098 – 1 022 679 days.

We take 5 instead of   5,011

5 x K1 = 5 x 400 = 2000 years,  where:  K1 = 400 from table 2

for interval  of 146 098 – 1 022 679 days.

5 x K2  = 730 485  days,   where:  K2 = 146 097 from the table 2

10.        732 088

- 730 485

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1 603 days – interval between January 01, 2001 AD and a solar date X.

11.   1603 : K2 = 1,097,  ,     where:  K2 = 1461 from the table 2

for interval  of 1462 – 35 064 days.

We take  1 instead of   1,097 and

1 x K1 = 1 x 4 = 4 years,   where:  K1 = 4  from the table 2

for interval  of 1096 – 1 461 days.

1 x K2  = 1461  days,   where:  K2 = 1461  from the table 2.

12.      1603 days

- 1461

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142 days   (the augend)   -  interval between January 01, 2005 AD and a solar date X.

13.    It is necessary to define a numbers of full months (Gregorian).

A nearest mini modMg (table 1) is 120 days, i.e.  the full months are the [1+2+3+4] months,

142 days

- 120

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22  days  - interval between May 01, 2005 AD and a solar date X.

14.    Date X  is equal to:

May 01, 2005 AD

+         22

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May 23, 2005 AD,   Weekday  -  Lunaday   (Full Moon Day).

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